Loading [MathJax]/jax/output/CommonHTML/jax.js
View

Mathematics/Linear Algebra

[Finite-Dimensional Linear Algebra] 2.5 + 2.6 + 2.7 Basis and Dimension

Lemma For a set of vectors u1,u2,,un in vector space V, if vsp{u1,u2,un}, then

sp{u1,u2,un,v}=sp{u1,u2,un}

This leads to the concept of a basis, a spanning set containing the fewest possible elements. 

Definition of a Basis

Let u1,u2,un be vectors in a vector space V. We say that {u1,u2,un} is a basis for V iff  {u1,u2,,un} is a spanning set for V and is linearly independent.

Definition of Linear Independence

Let V be a vector space over a field F. Let u1,u2,un be vectors in V, and let α1,α2,αn  be scalars in F. We say that {u1,u2,,un} is linearly independent iff  α1u1+α2u2++αnun=0 only when α1=α2==αn=0.

  • inversely, a set is linearly dependent iff there exists a nontrivial solution to α1=α2==αn=0 in which not all of the scalars αi are zero. 

Figure 2.5.1. Visualization of linear independence

Intuitively, linearly independent vectors represent different directions in a vector space, such as the x-axis and the y-axis that only have one common element, 0. 

 

Theory A set of vectors {u1,u2,un}, where n2, is linearly dependent iff at least one of the vectors can be written as a linear combination of the remaining n1 vectors. 

 

Lemma If a set of vectors {u1,u2,un} is linearly dependent, then there exists an integer k, with 2kn, such that uk is a linear combination of u1,u2,uk1

 

Theory A set of vectors {u1,u2,un} is linearly independent iff each vector in sp{u1,u2,un} can be written uniquely as a linear combination of u1,u2,un

 

Theory A set of vectors {u1,u2,un} is a basis for V iff each vector in vV can be written uniquely as a linear combination of u1,u2,un


Dimensions of a Vector Space

Definition of Finite-Dimensionality

Let V be a vector space over a field F. We say that V is finite-dimensional if

  • V has a basis or
  • V is a trivial vector space {0}.

If V is not finite-dimensional, then it is called infinite-dimensional. 

 

Corollary Every nontrivial subspace of a finite-dimensional vector space has a basis

 

Theorem Let V be a nontrivial vector space over a field F, and suppose {u1,u2,,um} spans V. Then a subset of the spanning set is a basis for V

 

Theorem Let V be a finite-dimensional vector space over a field F, and suppose {u1,u2,,uk} is linearly independent. If the linearly independent set of vectors does not span V, then there exist vectors uk+1,uk+2,,un such that {u1,u2,,uk,uk+1,,un} is a basis for V

 

Theorem Let V be a finite-dimensional vector space over a field F, and let {u1,u2,um} be a basis for V. If v1,v2,vn are any n vectors in V, with n>m, then the set {v1,v2,vn} is linearly dependent. 

 

Corollary Let {u1,u2,um} and {v1,v2,vm} be two bases for V. Then n=m.

Definition of Dimensions of a Vector Space

Let V be a finite-dimensional vector space.

  • If V is a trivial vector space, then we say that the dimension of V is zero. 
  • Else, the dimension of V is the number of vectors in a basis for V

 

Example The dimensions of Pn is n+1 since {1,x,x2,xn} is a basis. 

 

Theorem Let V be an n-dimensional vector space over a field F, and let u1,u2,un be vectors in V. 

  1. If {u1,u2,un} spans V, then it is linearly independent and hence a basis for V.
  2. If {u1,u2,un} is linearly independent, then it spans V and hence a basis for V

basis: a minimal spanning set for a vector space